PROC STDIZE is run with METHOD=MIDRANGE before clustering. What transformation does this apply?
Select an answer to reveal the explanation.
Short Explanation and Infographic
Here's the deal — b is correct because METHOD=MIDRANGE centers by subtracting (min+max)/2 and scales by dividing by (max-min)/2, resulting in values bounded in [-1, 1]. A describes METHOD=STD (z-score).
Full explanation below image
Full Explanation
B is correct because METHOD=MIDRANGE centers by subtracting (min+max)/2 and scales by dividing by (max-min)/2, resulting in values bounded in [-1, 1]. A describes METHOD=STD (z-score). C describes METHOD=RANGE which produces [0, 1]. D is not a valid PROC STDIZE METHOD= option.